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X^2+5X-2700=0
a = 1; b = 5; c = -2700;
Δ = b2-4ac
Δ = 52-4·1·(-2700)
Δ = 10825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10825}=\sqrt{25*433}=\sqrt{25}*\sqrt{433}=5\sqrt{433}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5\sqrt{433}}{2*1}=\frac{-5-5\sqrt{433}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5\sqrt{433}}{2*1}=\frac{-5+5\sqrt{433}}{2} $
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